3x^2-0.4+0.02=0

Solution for 3x^2-0.4+0.02=0 equation:

3x^2-0.4+0.02=0

We add all the numbers together, and all the variables

3x^2-0.38=0

a = 3; b = 0; c = -0.38;
Δ = b2-4ac
Δ = 02-4·3·(-0.38)
Δ = 4.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.56}}{2*3}=\frac{0-\sqrt{4.56}}{6}
=-\frac{\sqrt{}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.56}}{2*3}=\frac{0+\sqrt{4.56}}{6}
=\frac{\sqrt{}}{6}
$